SET-2 Banking Quiz

SET-2 Banking Quiz

Study the graph carefully and answer the following questions. Following pie chart shows the percentage distribution of number of players playing various games.

1. If the number of players playing Handball is sum of 80% and 50% of the number of players playing Cricket and Football respectively. Find the number of players playing Handball.

a) 2160

b) 2260

c) 2190

d) 2290

e) 2090

Answer: a) 2160

Number of players playing table tennis = 8% of 8000 = 640
Game Number of players
Table tennis 640
Cricket 1200
Football 2400
Hockey 880
Basketball 2880

80% of number of players playing cricket = 80/100 × 1200 = 960
50% of number of players playing football = 50/100 × 2400 = 1200
Number of players playing handball = 960 + 1200 = 2160

2. What is the difference between the number of players playing table tennis and hockey together to the number of players playing football?

a) 840

b) 850

c) 860

d) 870

e) 880

Answer: e) 880

Number of players playing table tennis = 8% of 8000 = 640

Game

Number of players

Table tennis

640

Cricket

1200

Football

2400

Hockey

880

Basketball

2880

 

Number of players playing table tennis and hockey together = 640 + 880 = 1520

Number of players playing football = 2400

Required difference = 2400 – 1520 = 880

3. If the ratio of male and female playing cricket is 3 : 2 and the ratio of female and male playing basketball is 2 : 3. Find the sum of number of male players playing cricket and basketball.

a) 2458

b) 2248

c) 2348

d) 2448

e) 2450

Answer: d) 2448

Number of players playing table tennis = 8% of 8000 = 640

Game

Number of players

Table tennis

640

Cricket

1200

Football

2400

Hockey

880

Basketball

2880

 

Number of male players playing cricket

Number of male players playing basketball

Required total = 720 + 1728 = 2448

4. What is the average of number of players playing cricket, football, and basketball?

a) 2160

b) 2260

c) 2250

d) 2360

e) 2420

Answer: a) 2160

Number of players playing table tennis = 8% of 8000 = 640

Game

Number of players

Table tennis

640

Cricket

1200

Football

2400

Hockey

880

Basketball

2880

Total number of players playing cricket, football and basketball = 1200 + 2400 + 2880

=> 6480

Required average = 6480/3 = 2160

5. What is the ratio of number of players playing hockey with respect to the number of players playing table tennis?

a) 11 : 10

b) 11 : 9

c) 13 : 8

d) 3 : 2

e) 11 : 8

Answer: e) 11 : 8

Number of players playing table tennis = 8% of 8000 = 640

Game

Number of players

Table tennis

640

Cricket

1200

Football

2400

Hockey

880

Basketball

2880

 

Required ratio = 880 : 640 = 11 : 8

6. What is the percentage of number of players playing cricket with respect to the number of players playing football?

a) 45%

b) 50%

c) 55%

d) 60%

e) 65%

Answer: b) 50%

Number of players playing table tennis = 8% of 8000 = 640

Game

Number of players

Table tennis

640

Cricket

1200

Football

2400

Hockey

880

Basketball

2880

Required percentage = 1200/2400 X 100= 50%

In the following question, two equations I and II are given. Solve both the equations carefully and choose the correct option.

7. (I) x2 - 3x - 10 = 0 (II) y2 - 14y + 45 = 0

a) y < x

b) x ≤ y

c) x = y or relationship cannot be established

d) x < y

e) x ≥ y

Answer: b) x ≤ y

(I) x2 – 3x – 10 = 0

=> (x + 2)(x – 5) = 0

=> x = -2 or 5

(II) y2 – 14y + 45 = 0

=> (y – 5)(y – 9) = 0

=> y = 5 or 9

Hence, x ≤ y

8. (I) 6x2 + 43x + 65 = 0 (II) 6y2 - 35y + 51 = 0

a) y < x

b) x ≤ y

c) x = y or relationship cannot be established

d) x < y

e) x ≥ y

Answer: d) x < y

(I) 6x2 + 43x + 65 = 0

=> (6x + 13)(x + 5) = 0

=> x = -2.16 or -5

(II) 6y2 – 35y + 51 = 0

=> (6y – 17)(y – 3) = 0

=> y = 2.83 or 3

Hence, x < y

9. I. 20x2 - x - 12 = 0 II. 20y2 + 27y + 9 = 0

a) y < x

b) x ≤ y

c) x = y or relationship cannot be established

d) x < y

e) x ≥ y

Answer: c) x = y or relationship cannot be established

From I, (5x-4)(4x+3) = 0

x = -3/4, 4/5

From II, (4y+3)(5y+3) = 0

y = -3/4, -3/5

-3/4 < -3/5 < 4/5

Since one value of y lies between the two values of x, the relationship cannot be established.

10. I. x2 +39x +374 = 0 II. y2 +15y +26 = 0

a) y < x

b) x ≤ y

c) x = y or relationship cannot be established

d) x < y

e) x ≥ y

Answer: d) x < y

From equation I:

x2 +39x +374 = (x + 22)(x + 17)= 0

=> x = -22, -17

From equation II:

y2 +15y +26 = (y + 13)(y + 2) = 0

=> y = -13, -2

So, x < y

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